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package bjc.dicelang.dice;
/**
* A die that represents two dice with an applied math operator.
*
* @author EVE
*
*/
public class MathDie implements Die {
/*
* @TODO 10/08/17 Ben Culkin :MathGeneralize
* Why do we have the operator types hardcoded, instead of just
* having a general thing for applying a binary operator to dice?
* Fix this by changing it to the more general form.
*/
/**
* The types of a math operator.
*
* @author EVE
*
*/
public static enum MathOp {
/** Add two dice. */
ADD,
/** Subtract two dice. */
SUBTRACT,
/** Multiply two dice. */
MULTIPLY;
@Override
public String toString() {
switch (this) {
case ADD:
return "+";
case SUBTRACT:
return "-";
case MULTIPLY:
return "*";
default:
return this.name();
}
}
}
private final MathDie.MathOp type;
private final Die left;
private final Die right;
/**
* Create a new math die.
*
* @param op
* The operator to apply.
*
* @param lft
* The left operand.
*
* @param rght
* The right operand.
*/
public MathDie(final MathDie.MathOp op, final Die lft, final Die rght) {
type = op;
left = lft;
right = rght;
}
@Override
public boolean canOptimize() {
return left.canOptimize() && right.canOptimize();
}
private long performOp(final long lft, final long rght) {
switch (type) {
case ADD:
return lft + rght;
case SUBTRACT:
return lft - rght;
case MULTIPLY:
return lft * rght;
default:
return 0;
}
}
@Override
public long optimize() {
final long lft = left.optimize();
final long rght = right.optimize();
return performOp(lft, rght);
}
@Override
public long roll() {
final long lft = left.roll();
final long rght = right.roll();
return performOp(lft, rght);
}
@Override
public long rollSingle() {
final long lft = left.rollSingle();
final long rght = right.rollSingle();
return performOp(lft, rght);
}
@Override
public String toString() {
return left.toString() + " " + type.toString() + " " + right.toString();
}
}
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